def solution(n):
    
    if n < 3:
        return n
    
    dp = [0] * (n + 1)
    dp[1], dp[2] = 1, 2
    
    for i in range(3, n + 1):
        dp[i] = dp[i - 1] + dp[i - 2]
        
    return dp[n] % 1234567

+ Recent posts